Frequently Asked Questions
Why does the copied current not exactly equal the reference current?
Several mechanisms cause the output current to deviate from the ideal mirror ratio. The most common are Vce mismatch (the output transistor operates at a different collector voltage than the reference transistor, so the Early effect shifts its current), base current loading (in BJTs, the base currents drawn from the reference node reduce the available reference current), and transistor mismatches (manufacturing variation in device geometry and doping). For precision applications, use a Wilson mirror or cascode mirror topology to suppress Vce sensitivity and base-current errors. For CMOS, use large-area transistors to minimize threshold mismatch and add cascode devices to improve output impedance.
Can I use a current mirror for AC signals?
Yes, current mirrors work for AC signals within their bandwidth. The bandwidth is limited by the transistor's transition frequency (fT) and by parasitic capacitances at the mirror nodes. The diode-connected reference transistor has significant input capacitance that, combined with any input source resistance, creates a low-pass pole. The Miller effect at the cascode node can also limit bandwidth in high-gain topologies. For wideband applications, choose high-fT transistors, minimize parasitic capacitances, and consider whether a simpler topology with lower output impedance might give better frequency response despite its lower DC accuracy.
How do I set the mirror ratio?
The ideal output current equals the reference current multiplied by the ratio of output device size to reference device size. In a MOSFET mirror you set the ratio by the width-to-length (W/L) ratio of the output transistor relative to the reference; in a BJT mirror you set it by the emitter-area ratio or by placing several matched output transistors in parallel. A ratio of 2 doubles the current, a ratio of 0.5 halves it, and a ratio of 1 copies it exactly.
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