Frequently Asked Questions
What standard does this calculator use?
IPC-2221. It computes the cross-sectional area a trace needs as Area = (I / (k × ΔT^0.44))^(1/0.725), with k = 0.048 for external traces and 0.024 for internal traces, then converts area to width using the copper weight.
Why do internal traces need to be wider?
Internal (buried) layers cannot shed heat to open air, so for the same current and temperature rise they need roughly double the width of an external surface trace. That is why the constant k is half as large for internal layers.
What temperature rise should I use?
The rise is the trace heating above ambient. 10°C is a common conservative default. Remember that a 10°C rise on a board already at 60°C means a 70°C conductor, so account for the real operating ambient.
Should I just make the trace wider for high current?
For high-current power paths it is usually better to use thicker copper (2 oz or more), add copper pours, or stitch multiple layers with vias rather than relying on an impractically wide trace. Treat the calculated width as a conservative minimum.
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Estimates for informational purposes only.
Important Disclaimer: Estimates for informational purposes only.
This calculator provides estimates for informational purposes only. Results are based on assumptions and may not reflect actual outcomes. Consult qualified professionals in relevant fields before making important decisions based on these results.