Combustion Reaction Calculator

Balance and calculate the stoichiometry of a complete combustion reaction for any hydrocarbon or organic fuel.

Frequently Asked Questions

What is the general equation for complete combustion of a hydrocarbon?

CxHy + (x + y/4) O2 -> x CO2 + (y/2) H2O. For propane (C3H8): C3H8 + 5O2 -> 3CO2 + 4H2O. If the molecule contains oxygen (CxHyOz), subtract the oxygen already present: the O2 coefficient becomes (x + y/4 - z/2). Complete combustion requires excess oxygen; insufficient oxygen produces CO and soot (incomplete combustion).

How much CO2 does burning 1 gallon of gasoline produce?

Gasoline is approximately C8H18 (octane). Burning 1 gallon (~2.8 kg, about 24.5 mol of octane) produces 24.5 x 8 = 196 mol of CO2, which weighs 196 x 44.009 = 8,625 g or about 8.6 kg of CO2. The EPA figure of 8.89 kg CO2 per gallon of regular gasoline (which includes the full carbon content) is consistent with this estimate.

What is the air-to-fuel ratio and why does it matter?

The stoichiometric air-to-fuel ratio is the exact mass of air needed for complete combustion. For gasoline it is about 14.7:1 (14.7 kg air per kg fuel). A lean mixture (> 14.7:1) has excess air - cleaner combustion but less power. A rich mixture (< 14.7:1) has insufficient air - incomplete combustion, more CO and unburned hydrocarbons. Modern engines use oxygen sensors to maintain the stoichiometric ratio.

Important Disclaimer: Estimates for informational purposes only.

This calculator provides estimates for informational purposes only. Results are based on assumptions and may not reflect actual outcomes. Consult qualified professionals in relevant fields before making important decisions based on these results.